Hydraulic Cylinder Force Calculator
Push and pull force of a hydraulic cylinder from bore, rod diameter and pressure — in kN and metric tons.
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Rod diameter must be smaller than bore
How the Force Is Calculated
A hydraulic cylinder turns fluid pressure into linear mechanical force through one simple relationship: Force = Pressure × Area (F = P × A). On the push stroke (extending), pressure acts on the full circular face of the piston, so F = π/4 · D² · P, where D is the bore diameter. On the pull stroke (retracting), fluid enters the rod-side chamber and pushes against an annular ring — the piston face minus the rod's cross-section — so F = π/4 · (D² − d²) · P, where d is the rod diameter. Because part of that working area is permanently occupied by the rod, every double-acting cylinder pulls with less force than it pushes.
The relationship between bore size and force is not linear, it is quadratic, because circular area scales with the square of the radius (A = π·r²). Enlarging a cylinder's bore by just 20% — say from Ø80 mm to Ø96 mm — increases the piston area, and therefore the force delivered at the same pressure, by roughly 44%. This is exactly why manufacturers can reach dramatically higher tonnage ratings with only a modest jump in bore diameter, and why engineers reach for a bigger bore, not more pressure, when a press or clamp needs significantly more force.
Worked example: a Ø100 mm bore with a Ø56 mm rod, running at 200 bar. Converting units (1 bar = 0.1 N/mm²): push force = π/4 · 100² · 20 ≈ 157,000 N ≈ 157 kN ≈ 16.0 metric tons. Pull force uses the annular area instead: π/4 · (100² − 56²) · 20 ≈ 108,600 N ≈ 108.6 kN ≈ 11.1 metric tons — about 69% of the push force, purely because the rod steals piston area on the way back.
What You Should Know
Force and speed are two sides of the same pump: both are set by flow rate (Q), not by pressure. Piston speed = Q ÷ A, so for a fixed pump output a smaller-bore cylinder travels faster (the same oil volume fills less area per millimeter of stroke) but produces less force at a given pressure; a larger bore is the mirror image — slower, but stronger. This is the classic force-speed trade-off behind why fast clamping cylinders and slow, powerful press cylinders look so different even on the same power unit.
- Real-world output typically reaches only 90-95% of the theoretical F = P × A value, because seal friction, back-pressure and small internal leaks consume some of the available force. This calculator reports the theoretical figure, the standard reference for sizing.
- Typical system pressures: 160-250 bar for standard industrial hydraulics, 250-350 bar for mobile equipment like excavators and loaders, and up to 700 bar for hand-operated hydraulic tools and jacks.
- Always size a cylinder against the relief-valve setting of its actual circuit — the cylinder only ever experiences the pressure the pump and valves deliver, never more, no matter how strong its components are rated.
Frequently Asked Questions
Why is pull force always lower than push?
The rod occupies part of the piston face on the retract side, so pressure acts on a smaller ring-shaped area. A Ø100 bore with a Ø56 rod retracts with about 69% of its extend force.
What pressure should I assume?
Standard industrial hydraulics run 160-250 bar; mobile equipment 250-350 bar; hand pumps up to 700 bar. Use your relief-valve setting — the cylinder only sees what the circuit delivers.
How do I convert kN to tons?
Divide by 9.81: 157 kN ≈ 16.0 metric tons of equivalent load. The tool shows both.
Why does a small increase in bore diameter make such a big difference in force?
Because piston area grows with the square of the radius, not linearly with diameter. A 20% larger bore — for example Ø80 mm to Ø96 mm — increases area, and therefore force at the same pressure, by about 44%. This quadratic relationship is why bore size, more than pressure, is the lever engineers pull when a press or clamp needs substantially more tonnage.
I need the cylinder to move faster — should I raise the pressure?
No — speed is set by flow rate, not pressure. Piston speed = flow ÷ piston area, so a faster stroke needs a higher-output pump or a smaller bore, not more bar. Raising pressure increases force, not speed; the two variables are independent, and this is the classic force-versus-speed trade-off in cylinder selection.
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Hydraulic Cylinder Force Calculator
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