Pulley Size & RPM Calculator
Driven pulley speed, drive ratio and belt speed from pulley diameters and motor RPM — works for sprockets and gears too.
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If you enter tooth counts, belt speed is not computed (needs diameters).
How the Ratio Is Calculated
A belt-and-pulley drive is governed by one physical fact: the belt cannot stretch or compress, so its linear speed must be identical everywhere it wraps a pulley. Since linear speed equals π × diameter × RPM, that constraint forces D₁ × N₁ = D₂ × N₂ — the driver pulley's diameter times its RPM equals the driven pulley's diameter times its RPM. Rearranged, the driven speed is N₂ = N₁ × (D₁ ÷ D₂): a small driver turning a large driven pulley slows the output shaft down, and a large driver turning a small driven pulley speeds it up. The same relationship governs chain sprockets and toothed gears — substitute tooth count for diameter, since tooth pitch plays the identical geometric role.
Worked example: a motor spins a 100 mm pulley at 1750 RPM and drives a 250 mm pulley on a pump shaft: N₂ = 1750 × (100 ÷ 250) = 700 RPM, a 2.5:1 reduction. Because energy is conserved (friction losses aside), the torque delivered to that shaft rises by the same 2.5:1 factor the speed dropped by — this is the entire point of gearing down: trading RPM for torque to start a heavy load or turn slow-running equipment. Flip the pulleys (250 mm driving 100 mm) and the output would instead speed up 2.5× while torque fell by the same factor.
The tool also reports belt speed, v = π · D₁ · N₁ ÷ 60,000 m/s, since that figure — not RPM — sets belt wear and safety limits: keep classical V-belts under roughly 30 m/s and narrow-profile V-belts under roughly 40 m/s.
What to Know
- Speed and torque trade off — gearing never creates either for free. A 2.5:1 speed reduction yields roughly a 2.5:1 torque increase (minus friction losses); you cannot lower RPM and raise torque beyond what the ratio allows.
- Center distance never enters the ratio. Only the two diameters (or tooth counts) set N₂ — how far apart the shafts sit changes belt length and wrap angle, not speed.
- Chains and timing belts carry the ratio exactly, with no slip, so N₂ is as precise as your diameter/tooth data; ordinary V-belts lose roughly 1-3% to slip under load, so real output speed runs a touch below theoretical.
- Multi-stage drives multiply. Two 2:1 reductions in series give 4:1 overall — a common way to reach a large ratio without one impractically oversized pulley.
- An idler or tensioner pulley doesn't touch the math. Since it is neither the driver nor the driven member, it changes belt tension and wrap angle only — it never appears in the D₁N₁ = D₂N₂ relationship.
Frequently Asked Questions
My motor runs 1450 RPM and I need 725 — what pulleys?
You need a 2:1 reduction, so the driven pulley must be twice the driver: e.g. 100 mm on the motor and 200 mm on the shaft. Any pair with that ratio works; larger pairs grip better and wear slower.
Does belt slip change the result?
V-belts slip 1-3% under load, so real driven speed runs slightly below theoretical. Timing belts, chains and gears have none — the equation is exact for them.
Which diameter do I measure?
The pitch diameter — where the belt's neutral line rides — not the outer edge. For V-belts it sits slightly below the rim; catalogs list it per groove profile.
Why does torque increase when RPM decreases?
Because mechanical power (ignoring friction) stays constant across the drive: power = torque × angular speed. If a pulley pair cuts RPM by a factor of 2.5, torque on the slower shaft rises by that same 2.5 factor — energy is neither created nor destroyed, just traded between speed and turning force.
Does adding an idler pulley change the ratio?
No. An idler only rides on the belt to add tension or change wrap angle around the driver and driven pulleys — it is not itself a power input or output, so it never appears in the D₁N₁ = D₂N₂ equation. Only the driver and driven diameters (or tooth counts) set the ratio.
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